Web1. Write a formula for the function f : N → R defined recursively as: (a) f (1) = 0, f (n) = f (n − 1) + (−1)n; (b) f (1) = 0, f (n) = nf (n − 1) + 1 n + 1 ; (c) f (1) = 1, f (n) = nf (n − 1) + 1 n + 1 . 2. Identify the sets X ⊂ Z defined by the following recursive definitions. (a) 0 ∈ X, x ∈ X → [x + 2 ∈ X] ∧ [x + 3 ∈ X]. WebMay 11, 2024 · QUESTION: Let f: N → N be the function defined by f ( 0) = 0 , f ( 1) = 1 and f ( n) = f ( n − 1) + f ( n − 2) for all n ≥ 2 , where N is the set of all non negative integers. Prove that f ( 5 n) is divisible by 5 for all n. MY ANSWER: It's clear that this is a Fibonacci sequence which goes like → 0, 1, 1, 2, 3, 5, 8, 13, 21,.......
一、离散时间傅里叶变换(DTFT) - CSDN博客
WebApr 14, 2024 · 少し前から里紗は何となく体調がよくないと自分でも感じていた。仕事は忙しかったが、これまでも仕事が忙しいことが苦になったことはなく、一ヶ月休みなく … WebMar 14, 2024 · 首先,我们可以将 x^2/1 (cosx)^2 写成 x^2 sec^2x 的形式。然后,我们可以使用分部积分法来求解不定积分。具体来说,我们可以令 u = x^2 和 dv = sec^2x dx,然后求出 du 和 v,最后代入分部积分公式即可得到不定积分的解。 great clips tiffin avenue
Formula for $1^2+2^2+3^2+...+n^2$ - Mathematics Stack Exchange
WebOct 29, 2024 · jimrgrant1 Answer: f (5) = 4375 Step-by-step explanation: Given f (n) = 5f (n - 1) and f (1) = 7 This allows us to find the next term in the sequence from the previous term f (2) = 5f (1) = 5 × 7 = 35 f (3) = 5f (2) = 5 × 35 = 175 f (4) = 5f (3) = 5 × 175 = 875 f (5) = 5f (4) = 5 × 875 = 4375 Advertisement WebApr 9, 2009 · Only numeric solution applies here. f is a function, f (n) is number. – Harry Apr 25, 2013 at 13:09 Show 4 more comments 378 How about: f (n) = sign (n) - (-1)ⁿ * n In Python: def f (n): if n == 0: return 0 if n >= 0: if n % 2 == 1: return n + 1 else: return -1 * (n - 1) else: if n % 2 == 1: return n - 1 else: return -1 * (n + 1) Web1 @evinda: You want f (n)/f (n)^2 = c (some constant), that means 1/f (n) = c or f (n) = 1/c, so that means f (n) must be a constant. – user541686 Feb 27, 2015 at 19:03 Show 9 more comments 16 If f (n) = O (g (n)), 2^ (f (n)) not equal to O (2^g (n))) Let, f (n) = 2log n and g (n) = log n (Assume log is to the base 2) great clips tiffany plaza denver